Consider a single phase induction motor with standstill rotor as shown in the Fig. 1. The stator winding is excited by the single phase a.c. supply. This supply produces an alternating flux Φs which acts along the axis of the stator winding. Due to this flux, e.m.f., gets induced in the rotor conductors due to transformer action. As rotor is closed one, this e.m.f. circulates current through the rotor conductors. The direction of the rotor current is as shown in the Fig. 1. The direction of rotor current is so as to oppose the cause producing it, which is stator flux Φs.
Now Fleming’s left hand rule can be used to find the direction of the force experienced by the rotor conductors. It can be seen that when Φs acts in upward direction and increasing positively, the conductors on left experience force from left to right while conductors on right experience force from right to left. Thus overall, the force experienced by the rotor is zero. Hence no torque exists on the rotor and rotor can not start rotating.
We have seen that there must exist two fluxes separated by some angle so as to produce rotating magnetic field. According to cross field theory, the stator flux can be resolved into two components which are mutually perpendicular. One acts along axis of the stator winding and other acts perpendicular to it.
Assume now that an initial push is given to the rotor anticlockwise direction. Due to the rotation, rotor physically cuts the stator flux and dynamically e.m.f. gets induced in the rotor. This is called speed e.m.f. or rotational e.m.f. The direction of such e.m.f. can be obtained by Flemung’s right hand rule and this e.m.f. in phase with the stator flux Φs. The direction of e.m.f. is shown in the Fig. 2. This e.m.f. us denoted as E2N. This e.m.f. circulates current through rotor which is I2N. This current produces its own flux called rotor flux Φr. This axis of Φr is at 90o to the axis of stator flux hence this rotor flux is called cross-field.
Due to very high rotor reactance, the rotor current I2N and Φr lags the rotational e.m.f. by almost 90o .
Thus Φr is in quadrature with Φs in space and lags Φs by 90o in time phase. Such two fluxes produce the rotating magnetic field.
The direction of this rotating magnetic field will be same as the direction of the initial push given. Thus rotor experiences a torque in the same direction as that of rotating magnetic field i.e. the direction of initial push. So rotor accelerates in the anticlockwise direction under the case considered and attains a subsynchronous speed in the steady state.